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  1. #include <stdio.h> 
  2. void print(int *arr, int m, int n) 
  3. { 
  4.     int i, j; 
  5.     for (i = 0; i < m; i++) 
  6.       for (j = 0; j < n; j++) 
  7.         printf("%d ", *((arr+i*n)+j)); 
  8. } 
  9.  
  10. int main() 
  11. { 
  12.     int arr[][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}; 
  13.     int m = 3, n = 3; 
  14.  
  15.     // We can also use "print(&arr[0][0], m, n);" 
  16.     print((int *)arr, m, n); 
  17.     return 0; 
  18. }
Success #stdin #stdout 0s 4516KB
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https://ideone.com/Q3PkFf
language:
C (gcc 8.3)
created:
4 years ago
visibility:
public

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