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  1. #include <stdio.h>
  2. //正の偶数nを引数とし，以下の正の偶数の和を求める関数
  3. int rec(int n){
  4.     if (n >12){
  5.         return 0;
  6.     }
  7.     else{
  8.         return n+rec(n+2);
  9.     }
  10. }
  11. int main(void) {
  12.     int n;
  13.  
  14.     printf("11以下の正の偶数の和は%d\n", rec(2));
  15. 	return 0;
  16.  
  17. }
  18.  
Success #stdin #stdout 0s 5316KB
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11以下の正の偶数の和は42
https://ideone.com/t1JMqe
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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