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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n <=2){
  5.         return 2;
  6.     }
  7.         return n+rec(n-2);
  8. }
  9. int main(void) {
  10.     int n = 12;
  11.     printf("%d以下の正の偶数の和は%d\n", n, rec(n));
  12. 	return 0;
  13. }
Success #stdin #stdout 0s 5296KB
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12以下の正の偶数の和は42
https://ideone.com/s4ODn1
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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