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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n == 1){
  5.         return 1;
  6.     }
  7.     else if(n%2!=0){
  8.     	return n+rec(n-2);
  9.     }
  10.     else if(n==2){
  11.     	return 2;
  12.     }
  13.     else{
  14.     	return n+rec(n-2);
  15.     }
  16.  
  17.  
  18. }
  19. int main(void) {
  20.     int n = 10;
  21.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  22. 	return 0;
  23. }
Success #stdin #stdout 0s 5324KB
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10以下の正の奇数の和は30
https://ideone.com/rmiKAn
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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