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  1. $sqlite3 Mydb;
  2. CREATE TABLE
  3. Persons(
  4. PersonID int,
  5. Name varchar(23),
  6. City varchar(23)
  7. );
  8. INSERT INTO Persons(PersonID,Name,City)VALUES('1','Emeka','Warri');
Success #stdin #stdout #stderr 0.01s 5280KB
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Error: near line 1: near "$sqlite3": syntax error
https://ideone.com/bhu3HG
language:
SQLite (sqlite 3.27.2)
created:
13 days ago
visibility:
public

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