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  1. def performOps(A):
  2.     m = len(A)
  3.     n = len(A[0])
  4.     B = []
  5.     for i in xrange(len(A)):
  6.         B.append([0] * n)
  7.         for j in xrange(len(A[i])):
  8.             B[i][n - 1 - j] = A[i][j]
  9.     return B
  10.  
Success #stdin #stdout 0.02s 7140KB
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[[1,2,3,4],[5,6,7,8],[9,10,11,12]]
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Standard output is empty
https://ideone.com/Z5RWwA
language:
Python (cpython 2.7.16)
created:
2 years ago
visibility:
public

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