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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n)
  4. {
  5.     if (n == 1)
  6.     {
  7.         return 1;
  8.     }
  9.     else
  10.     {
  11.         return n+ rec(n-2);
  12.     }
  13. }
  14. int main(void) 
  15. {
  16.     int n = 11;
  17.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  18. 	return 0;
  19. }
Success #stdin #stdout 0s 5308KB
comments (?)
stdin 
Standard input is empty
stdout 
11以下の正の奇数の和は36
https://ideone.com/W4nNrY
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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