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  1. #include <iostream>
  2. //#include <vector>
  3. #include <omp.h>
  4. #include <climits>
  5. using namespace std;
  6. void min_reduction(int arr[], int n) {
  7.   int min_value = INT_MAX;
  8.   #pragma omp parallel for reduction(min: min_value)
  9.   for (int i = 0; i < n; i++) {
  10. 	if (arr[i] < min_value) {
  11.   	min_value = arr[i];
  12. 	}
  13.   }
  14.   cout << "Minimum value: " << min_value << endl;
  15. }
  16. void max_reduction(int arr[], int n) {
  17.   int max_value = INT_MIN;
  18.   #pragma omp parallel for reduction(max: max_value)
  19.   for (int i = 0; i < n; i++) {
  20. 	if (arr[i] > max_value) {
  21.   	max_value = arr[i];
  22. 	}
  23.   }
  24.   cout << "Maximum value: " << max_value << endl;
  25. }
  26. void sum_reduction(int arr[], int n) {
  27.   int sum = 0;
  28.    #pragma omp parallel for reduction(+: sum)
  29.    for (int i = 0; i < n; i++) {
  30. 	sum += arr[i];
  31.   }
  32.   cout << "Sum: " << sum << endl;
  33. }
  34. void average_reduction(int arr[], int n) {
  35.   int sum = 0;
  36.   #pragma omp parallel for reduction(+: sum)
  37.   for (int i = 0; i < n; i++) {
  38. 	sum += arr[i];
  39.   }
  40.   cout << "Average: " << (double)sum / (n-1) << endl;
  41. }
  42. int main() {
  43.     int *arr,n;
  44.     cout<<"\n enter total no of elements=>";
  45.     cin>>n;
  46.     arr=new int[n];
  47.     cout<<"\n enter elements=>";
  48.     for(int i=0;i<n;i++)
  49.     {
  50.    	 cin>>arr[i];
  51.     }
  52. //   int arr[] = {5, 2, 9, 1, 7, 6, 8, 3, 4};
  53. //   int n = size(arr);
  54.   min_reduction(arr, n);
  55.   max_reduction(arr, n);
  56.   sum_reduction(arr, n);
  57.   average_reduction(arr, n);
  58. }
Success #stdin #stdout 0.01s 5280KB
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stdin
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Standard input is empty
stdout
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 enter total no of elements=>
 enter elements=>Minimum value: 0
Maximum value: 0
Sum: 0
Average: 0
https://ideone.com/RIlJAd
language:
C++ (gcc 8.3)
created:
9 days ago
visibility:
public

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