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  1.  
  2. #include <stdio.h>
  3.  
  4. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  5. int rec(int n){
  6.     if (n == 1){
  7.         return 1;
  8.     }
  9.     else{
  10.         return n + rec(n - 2);
  11.     }
  12. }
  13.  
  14. int main(void) {
  15.     int n = 11;
  16.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  17.     return 0;
  18. }
  19.  
  20.  
Success #stdin #stdout 0s 5320KB
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11以下の正の奇数の和は36
https://ideone.com/JtvP93
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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