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  1. def second_largest(nums):
  2.     if len(set(nums)) < 2:
  3.         return None
  4.     unique_nums = list(set(nums))
  5.     unique_nums.sort()
  6.     return unique_nums[-2]
  7.  
  8. # Example Usage
  9. print(second_largest([4, 2, 6, 6, 2, 1]))  # Output: 4
  10. print(second_largest([7]))  # Output: None
Success #stdin #stdout 0.02s 9700KB
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4
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https://ideone.com/mvSq4F
language:
Python 3 (python  3.9.5)
created:
2 days ago
visibility:
public

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