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  1. // C++ program to find circular tour for a truck
  2. #include <bits/stdc++.h>
  3. using namespace std;
  4.  
  5. // A petrol pump has petrol and distance to next petrol pump
  6. class petrolPump {
  7. public:
  8. 	int petrol;
  9. 	int distance;
  10. };
  11.  
  12. // The function returns starting point if there is a
  13. // possible solution, otherwise returns -1
  14. int printTour(petrolPump p[], int n)
  15. {
  16. 	// deficit is used to store the value of the capacity as
  17. 	// soon as the value of capacity becomes negative so as
  18. 	// not to traverse the array twice in order to get the
  19. 	// solution
  20. 	int start = 0, deficit = 0;
  21. 	int capacity = 0;
  22. 	for (int i = 0; i < n; i++) {
  23. 		capacity += p[i].petrol - p[i].distance;
  24. 		if (capacity < 0) {
  25. 			// If this particular step is not done then the
  26. 			// between steps would be redundant
  27. 			start = i + 1;
  28. 			deficit += capacity;
  29. 			capacity = 0;
  30. 		}
  31. 	}
  32. 	return (capacity + deficit >= 0) ? start : -1;
  33. }
  34. // Driver code
  35. int main()
  36. {
  37. petrolPump arr[] = {{3, }, { 6, 4 }, { 3, 6 }, { 7, 3 } };
  38.  
  39. 	int n = sizeof(arr) / sizeof(arr[0]);
  40. 	int start = printTour(arr, n);
  41.  
  42. 	(start == -1) ? cout << "No solution"
  43. 				: cout << "Start = " << start;
  44.  
  45. 	return 0;
  46. }
  47.  
  48. // This code is contributed by aditya kumar
  49.  
Success #stdin #stdout 0.01s 5548KB
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Standard input is empty
stdout
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Start = 0
https://ideone.com/5B7rQp
language:
C++ (gcc 8.3)
created:
1 year ago
visibility:
public

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