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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. bool czyprostokatny(int a, int b, int c){
  5.     int na = a * a;
  6.     int nb = b * b;
  7.     int nc = c * c;
  8.     if(na + nb == nc){
  9.         return true;
  10.     }
  11.     if(na + nc == nb){
  12.         return true;
  13.     }
  14.     if(nb + nc == na){
  15.         return true;
  16.     }
  17.     return false;
  18. }
  19.  
  20.  
  21. int main() {
  22. 	int tab[3][3];
  23. 	for(int i = 0; i < 3; i++){
  24. 		for(int j = 0; j < 3; j++){
  25. 			cin >> tab[i][j];
  26. 		}
  27. 	}
  28.  
  29. 	for(int i = 1; i < 3; i++){
  30.         if(czyprostokatny(tab[i-1][0], tab[i-1][1], tab[i-1][2]) && czyprostokatny(tab[i][0], tab[i][1], tab[i][2])){
  31.             cout << tab[i-1][0] << " " << tab[i-1][1] << " " << tab[i-1][2] << endl;
  32.             cout << tab[i][0] << " " << tab[i][1] << " " << tab[i][2] << endl;
  33.         }
  34.         cout << endl;
  35.     }
  36.  
  37. 	return 0;
  38. }
Success #stdin #stdout 0s 5260KB
comments (?)
stdin 
1 1 1
3 4 5
5 12 13
stdout 
3 4 5
5 12 13
https://ideone.com/dikyC3
language:
C++ (gcc 8.3)
created:
14 days ago
visibility:
public

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